Comments on: Avoiding nested blocks

By: Anonymous

Anonymous — Wed, 09 Sep 2009 21:50:38 +0000

dang true. my fault, thanks for your answer

By: hakunin

hakunin — Wed, 09 Sep 2009 15:09:33 +0000

This won’t work because the block has to run nested within all stream-silencing blocks.

silence_stream(particular_stream) do # code for which stream is silenced end

In your case you’re silencing all streams individually, and not running any code in them. Then in the end you’re only silencing one last stream for &block passed in. Basically

stream.each

line in your example is meaningless.

By: Anonymous

Anonymous — Wed, 09 Sep 2009 15:02:07 +0000

do something like def silence_streams(*streams, &block) s = streams.pop streams.each {|s| silence_stream(s){} } silence_stream s, &block
end so the block doesn't get executed twice

By: hakunin

hakunin — Mon, 10 Aug 2009 16:53:25 +0000

Maybe I’m misunderstanding but wouldn’t this execute

&block

separately in each silence_stream? It looks like it’s equivalent of saying sequentially.

silence_stream(STDOUT) { same_code; } silence_stream(STDERR) { same_code; }

By: Nicolás Sanguinetti

Nicolás Sanguinetti — Mon, 10 Aug 2009 16:34:00 +0000

Why not

def silence_streams(*streams, &block) streams.each {|s| silence_stream(s, &block) } end

It's more concise, clearer at first sight, and more efficient, IMO.